3.23.90 \(\int \frac {(1-2 x)^{5/2}}{(2+3 x) \sqrt {3+5 x}} \, dx\)

Optimal. Leaf size=106 \[ -\frac {1}{15} \sqrt {5 x+3} (1-2 x)^{3/2}-\frac {239}{450} \sqrt {5 x+3} \sqrt {1-2 x}-\frac {17687 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )}{1350 \sqrt {10}}-\frac {98}{27} \sqrt {7} \tan ^{-1}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {5 x+3}}\right ) \]

________________________________________________________________________________________

Rubi [A]  time = 0.04, antiderivative size = 106, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.269, Rules used = {102, 154, 157, 54, 216, 93, 204} \begin {gather*} -\frac {1}{15} \sqrt {5 x+3} (1-2 x)^{3/2}-\frac {239}{450} \sqrt {5 x+3} \sqrt {1-2 x}-\frac {17687 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )}{1350 \sqrt {10}}-\frac {98}{27} \sqrt {7} \tan ^{-1}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {5 x+3}}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(1 - 2*x)^(5/2)/((2 + 3*x)*Sqrt[3 + 5*x]),x]

[Out]

(-239*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/450 - ((1 - 2*x)^(3/2)*Sqrt[3 + 5*x])/15 - (17687*ArcSin[Sqrt[2/11]*Sqrt[3
+ 5*x]])/(1350*Sqrt[10]) - (98*Sqrt[7]*ArcTan[Sqrt[1 - 2*x]/(Sqrt[7]*Sqrt[3 + 5*x])])/27

Rule 54

Int[1/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_.) + (d_.)*(x_)]), x_Symbol] :> Dist[2/Sqrt[b], Subst[Int[1/Sqrt[b*c -
a*d + d*x^2], x], x, Sqrt[a + b*x]], x] /; FreeQ[{a, b, c, d}, x] && GtQ[b*c - a*d, 0] && GtQ[b, 0]

Rule 93

Int[(((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_))/((e_.) + (f_.)*(x_)), x_Symbol] :> With[{q = Denomin
ator[m]}, Dist[q, Subst[Int[x^(q*(m + 1) - 1)/(b*e - a*f - (d*e - c*f)*x^q), x], x, (a + b*x)^(1/q)/(c + d*x)^
(1/q)], x]] /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[m + n + 1, 0] && RationalQ[n] && LtQ[-1, m, 0] && SimplerQ[
a + b*x, c + d*x]

Rule 102

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(b*(a +
b*x)^(m - 1)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(d*f*(m + n + p + 1)), x] + Dist[1/(d*f*(m + n + p + 1)), I
nt[(a + b*x)^(m - 2)*(c + d*x)^n*(e + f*x)^p*Simp[a^2*d*f*(m + n + p + 1) - b*(b*c*e*(m - 1) + a*(d*e*(n + 1)
+ c*f*(p + 1))) + b*(a*d*f*(2*m + n + p) - b*(d*e*(m + n) + c*f*(m + p)))*x, x], x], x] /; FreeQ[{a, b, c, d,
e, f, n, p}, x] && GtQ[m, 1] && NeQ[m + n + p + 1, 0] && IntegersQ[2*m, 2*n, 2*p]

Rule 154

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[(h*(a + b*x)^m*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(d*f*(m + n + p + 2)), x] + Dist[1/(d*f*(m + n
+ p + 2)), Int[(a + b*x)^(m - 1)*(c + d*x)^n*(e + f*x)^p*Simp[a*d*f*g*(m + n + p + 2) - h*(b*c*e*m + a*(d*e*(
n + 1) + c*f*(p + 1))) + (b*d*f*g*(m + n + p + 2) + h*(a*d*f*m - b*(d*e*(m + n + 1) + c*f*(m + p + 1))))*x, x]
, x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && GtQ[m, 0] && NeQ[m + n + p + 2, 0] && IntegersQ[2*m, 2
*n, 2*p]

Rule 157

Int[(((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)))/((a_.) + (b_.)*(x_)), x_Symbol]
:> Dist[h/b, Int[(c + d*x)^n*(e + f*x)^p, x], x] + Dist[(b*g - a*h)/b, Int[((c + d*x)^n*(e + f*x)^p)/(a + b*x
), x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x]

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 216

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[(Rt[-b, 2]*x)/Sqrt[a]]/Rt[-b, 2], x] /; FreeQ[{a, b}
, x] && GtQ[a, 0] && NegQ[b]

Rubi steps

\begin {align*} \int \frac {(1-2 x)^{5/2}}{(2+3 x) \sqrt {3+5 x}} \, dx &=-\frac {1}{15} (1-2 x)^{3/2} \sqrt {3+5 x}+\frac {1}{30} \int \frac {(4-239 x) \sqrt {1-2 x}}{(2+3 x) \sqrt {3+5 x}} \, dx\\ &=-\frac {239}{450} \sqrt {1-2 x} \sqrt {3+5 x}-\frac {1}{15} (1-2 x)^{3/2} \sqrt {3+5 x}+\frac {1}{450} \int \frac {-179-\frac {17687 x}{2}}{\sqrt {1-2 x} (2+3 x) \sqrt {3+5 x}} \, dx\\ &=-\frac {239}{450} \sqrt {1-2 x} \sqrt {3+5 x}-\frac {1}{15} (1-2 x)^{3/2} \sqrt {3+5 x}-\frac {17687 \int \frac {1}{\sqrt {1-2 x} \sqrt {3+5 x}} \, dx}{2700}+\frac {343}{27} \int \frac {1}{\sqrt {1-2 x} (2+3 x) \sqrt {3+5 x}} \, dx\\ &=-\frac {239}{450} \sqrt {1-2 x} \sqrt {3+5 x}-\frac {1}{15} (1-2 x)^{3/2} \sqrt {3+5 x}+\frac {686}{27} \operatorname {Subst}\left (\int \frac {1}{-7-x^2} \, dx,x,\frac {\sqrt {1-2 x}}{\sqrt {3+5 x}}\right )-\frac {17687 \operatorname {Subst}\left (\int \frac {1}{\sqrt {11-2 x^2}} \, dx,x,\sqrt {3+5 x}\right )}{1350 \sqrt {5}}\\ &=-\frac {239}{450} \sqrt {1-2 x} \sqrt {3+5 x}-\frac {1}{15} (1-2 x)^{3/2} \sqrt {3+5 x}-\frac {17687 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {3+5 x}\right )}{1350 \sqrt {10}}-\frac {98}{27} \sqrt {7} \tan ^{-1}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {3+5 x}}\right )\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]  time = 0.12, size = 108, normalized size = 1.02 \begin {gather*} \frac {30 \sqrt {-(1-2 x)^2} \sqrt {5 x+3} (60 x-269)-49000 \sqrt {14 x-7} \tan ^{-1}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {5 x+3}}\right )+17687 \sqrt {10-20 x} \sinh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {2 x-1}\right )}{13500 \sqrt {2 x-1}} \end {gather*}

Warning: Unable to verify antiderivative.

[In]

Integrate[(1 - 2*x)^(5/2)/((2 + 3*x)*Sqrt[3 + 5*x]),x]

[Out]

(30*Sqrt[-(1 - 2*x)^2]*Sqrt[3 + 5*x]*(-269 + 60*x) + 17687*Sqrt[10 - 20*x]*ArcSinh[Sqrt[5/11]*Sqrt[-1 + 2*x]]
- 49000*Sqrt[-7 + 14*x]*ArcTan[Sqrt[1 - 2*x]/(Sqrt[7]*Sqrt[3 + 5*x])])/(13500*Sqrt[-1 + 2*x])

________________________________________________________________________________________

IntegrateAlgebraic [A]  time = 0.18, size = 127, normalized size = 1.20 \begin {gather*} -\frac {11 \sqrt {1-2 x} \left (\frac {1525 (1-2 x)}{5 x+3}+478\right )}{450 \sqrt {5 x+3} \left (\frac {5 (1-2 x)}{5 x+3}+2\right )^2}+\frac {17687 \tan ^{-1}\left (\frac {\sqrt {\frac {5}{2}} \sqrt {1-2 x}}{\sqrt {5 x+3}}\right )}{1350 \sqrt {10}}-\frac {98}{27} \sqrt {7} \tan ^{-1}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {5 x+3}}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(1 - 2*x)^(5/2)/((2 + 3*x)*Sqrt[3 + 5*x]),x]

[Out]

(-11*Sqrt[1 - 2*x]*(478 + (1525*(1 - 2*x))/(3 + 5*x)))/(450*Sqrt[3 + 5*x]*(2 + (5*(1 - 2*x))/(3 + 5*x))^2) + (
17687*ArcTan[(Sqrt[5/2]*Sqrt[1 - 2*x])/Sqrt[3 + 5*x]])/(1350*Sqrt[10]) - (98*Sqrt[7]*ArcTan[Sqrt[1 - 2*x]/(Sqr
t[7]*Sqrt[3 + 5*x])])/27

________________________________________________________________________________________

fricas [A]  time = 1.12, size = 102, normalized size = 0.96 \begin {gather*} \frac {1}{450} \, {\left (60 \, x - 269\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1} - \frac {49}{27} \, \sqrt {7} \arctan \left (\frac {\sqrt {7} {\left (37 \, x + 20\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{14 \, {\left (10 \, x^{2} + x - 3\right )}}\right ) + \frac {17687}{27000} \, \sqrt {10} \arctan \left (\frac {\sqrt {10} {\left (20 \, x + 1\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{20 \, {\left (10 \, x^{2} + x - 3\right )}}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(5/2)/(2+3*x)/(3+5*x)^(1/2),x, algorithm="fricas")

[Out]

1/450*(60*x - 269)*sqrt(5*x + 3)*sqrt(-2*x + 1) - 49/27*sqrt(7)*arctan(1/14*sqrt(7)*(37*x + 20)*sqrt(5*x + 3)*
sqrt(-2*x + 1)/(10*x^2 + x - 3)) + 17687/27000*sqrt(10)*arctan(1/20*sqrt(10)*(20*x + 1)*sqrt(5*x + 3)*sqrt(-2*
x + 1)/(10*x^2 + x - 3))

________________________________________________________________________________________

giac [B]  time = 1.74, size = 173, normalized size = 1.63 \begin {gather*} \frac {49}{270} \, \sqrt {70} \sqrt {10} {\left (\pi + 2 \, \arctan \left (-\frac {\sqrt {70} \sqrt {5 \, x + 3} {\left (\frac {{\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}^{2}}{5 \, x + 3} - 4\right )}}{140 \, {\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}}\right )\right )} + \frac {1}{2250} \, {\left (12 \, \sqrt {5} {\left (5 \, x + 3\right )} - 305 \, \sqrt {5}\right )} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5} - \frac {17687}{27000} \, \sqrt {10} {\left (\pi + 2 \, \arctan \left (-\frac {\sqrt {5 \, x + 3} {\left (\frac {{\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}^{2}}{5 \, x + 3} - 4\right )}}{4 \, {\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}}\right )\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(5/2)/(2+3*x)/(3+5*x)^(1/2),x, algorithm="giac")

[Out]

49/270*sqrt(70)*sqrt(10)*(pi + 2*arctan(-1/140*sqrt(70)*sqrt(5*x + 3)*((sqrt(2)*sqrt(-10*x + 5) - sqrt(22))^2/
(5*x + 3) - 4)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22)))) + 1/2250*(12*sqrt(5)*(5*x + 3) - 305*sqrt(5))*sqrt(5*x +
3)*sqrt(-10*x + 5) - 17687/27000*sqrt(10)*(pi + 2*arctan(-1/4*sqrt(5*x + 3)*((sqrt(2)*sqrt(-10*x + 5) - sqrt(
22))^2/(5*x + 3) - 4)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22))))

________________________________________________________________________________________

maple [A]  time = 0.02, size = 98, normalized size = 0.92 \begin {gather*} -\frac {\sqrt {-2 x +1}\, \sqrt {5 x +3}\, \left (-3600 \sqrt {-10 x^{2}-x +3}\, x +17687 \sqrt {10}\, \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right )-49000 \sqrt {7}\, \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right )+16140 \sqrt {-10 x^{2}-x +3}\right )}{27000 \sqrt {-10 x^{2}-x +3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((-2*x+1)^(5/2)/(3*x+2)/(5*x+3)^(1/2),x)

[Out]

-1/27000*(-2*x+1)^(1/2)*(5*x+3)^(1/2)*(17687*10^(1/2)*arcsin(20/11*x+1/11)-49000*7^(1/2)*arctan(1/14*(37*x+20)
*7^(1/2)/(-10*x^2-x+3)^(1/2))-3600*(-10*x^2-x+3)^(1/2)*x+16140*(-10*x^2-x+3)^(1/2))/(-10*x^2-x+3)^(1/2)

________________________________________________________________________________________

maxima [A]  time = 1.18, size = 69, normalized size = 0.65 \begin {gather*} \frac {2}{15} \, \sqrt {-10 \, x^{2} - x + 3} x - \frac {17687}{27000} \, \sqrt {10} \arcsin \left (\frac {20}{11} \, x + \frac {1}{11}\right ) + \frac {49}{27} \, \sqrt {7} \arcsin \left (\frac {37 \, x}{11 \, {\left | 3 \, x + 2 \right |}} + \frac {20}{11 \, {\left | 3 \, x + 2 \right |}}\right ) - \frac {269}{450} \, \sqrt {-10 \, x^{2} - x + 3} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(5/2)/(2+3*x)/(3+5*x)^(1/2),x, algorithm="maxima")

[Out]

2/15*sqrt(-10*x^2 - x + 3)*x - 17687/27000*sqrt(10)*arcsin(20/11*x + 1/11) + 49/27*sqrt(7)*arcsin(37/11*x/abs(
3*x + 2) + 20/11/abs(3*x + 2)) - 269/450*sqrt(-10*x^2 - x + 3)

________________________________________________________________________________________

mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\left (1-2\,x\right )}^{5/2}}{\left (3\,x+2\right )\,\sqrt {5\,x+3}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1 - 2*x)^(5/2)/((3*x + 2)*(5*x + 3)^(1/2)),x)

[Out]

int((1 - 2*x)^(5/2)/((3*x + 2)*(5*x + 3)^(1/2)), x)

________________________________________________________________________________________

sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (1 - 2 x\right )^{\frac {5}{2}}}{\left (3 x + 2\right ) \sqrt {5 x + 3}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)**(5/2)/(2+3*x)/(3+5*x)**(1/2),x)

[Out]

Integral((1 - 2*x)**(5/2)/((3*x + 2)*sqrt(5*x + 3)), x)

________________________________________________________________________________________